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21x^2+29x+9=0
a = 21; b = 29; c = +9;
Δ = b2-4ac
Δ = 292-4·21·9
Δ = 85
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-\sqrt{85}}{2*21}=\frac{-29-\sqrt{85}}{42} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+\sqrt{85}}{2*21}=\frac{-29+\sqrt{85}}{42} $
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